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repository:cirque_du_soleil_stunt [2021/02/18 19:34]
porcaro1
repository:cirque_du_soleil_stunt [2021/02/18 19:36] (current)
porcaro1 [Answer Key]
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 ====Answer Key==== ====Answer Key====
 ===Handout=== ===Handout===
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 {{ :​repository:​cirque_du_soleil_velocities.png?​nolink&​600|}} {{ :​repository:​cirque_du_soleil_velocities.png?​nolink&​600|}}
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 To find the appropriate velocity of the airbag, we must divide this problem into several parts. Since horizontal and vertical motion are independent,​ we can first find the total time it will take for the bike to fall to the ground. Looking at the code, we see that for the provided target size and table height, the total distance the bike will fall is 1.25 meters. Knowing that the acceleration due to gravity is approximately -10 meters per second per second, we can use the following kinematic equation to solve for time: $y=y_0+v_yt+\dfrac{1}{2}a_yt^2$. Plugging in our knowns, we find $0=1.25-10t^2$. Rearranging and solving for $t$, we calculate that the total time it takes for the bike to hit the target once it falls off the cliff is 0.5 seconds. ​ To find the appropriate velocity of the airbag, we must divide this problem into several parts. Since horizontal and vertical motion are independent,​ we can first find the total time it will take for the bike to fall to the ground. Looking at the code, we see that for the provided target size and table height, the total distance the bike will fall is 1.25 meters. Knowing that the acceleration due to gravity is approximately -10 meters per second per second, we can use the following kinematic equation to solve for time: $y=y_0+v_yt+\dfrac{1}{2}a_yt^2$. Plugging in our knowns, we find $0=1.25-10t^2$. Rearranging and solving for $t$, we calculate that the total time it takes for the bike to hit the target once it falls off the cliff is 0.5 seconds. ​
  
  • repository/cirque_du_soleil_stunt.txt
  • Last modified: 2021/02/18 19:36
  • by porcaro1