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repository:terminal_velocity [2020/09/01 17:03] porcaro1 |
repository:terminal_velocity [2021/02/18 19:16] porcaro1 |
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| ====Activity==== | ====Activity==== | ||
| ===Handout=== | ===Handout=== | ||
| - | ** Terminal Velocity ** | ||
| {{ :repository:terminal_velocity.png?nolink&600|}} | {{ :repository:terminal_velocity.png?nolink&600|}} | ||
| + | ** Terminal Velocity ** | ||
| + | |||
| A coin is being dropped from the top of a building. When will it reach terminal velocity? How does the force of gravity compare to the force of air resistance? Take a look at the [[https://www.glowscript.org/#/user/david.pastula/folder/MyPrograms/program/TerminalVelocity-MinimalProgram/edit | unfinished code]] and answer the following questions: | A coin is being dropped from the top of a building. When will it reach terminal velocity? How does the force of gravity compare to the force of air resistance? Take a look at the [[https://www.glowscript.org/#/user/david.pastula/folder/MyPrograms/program/TerminalVelocity-MinimalProgram/edit | unfinished code]] and answer the following questions: | ||
| ==Pre-coding Questions== | ==Pre-coding Questions== | ||
| Line 36: | Line 37: | ||
| - Reflect on your predicted graphs. Explain how they were similar/different than your coding graphs. Revise your graphs as needed. | - Reflect on your predicted graphs. Explain how they were similar/different than your coding graphs. Revise your graphs as needed. | ||
| ===Code=== | ===Code=== | ||
| - | [[https://www.glowscript.org/#/user/david.pastula/folder/MyPrograms/program/TerminalVelocity-MinimalProgram/edit | Link]] | + | [[hthttps://www.glowscript.org/#/user/porcaro1/folder/RepositoryPrograms/program/TerminalVelocity-Incomplete | Link]] |
| <code Python [enable_line_numbers="true"]> | <code Python [enable_line_numbers="true"]> | ||
| GlowScript 2.8 VPython | GlowScript 2.8 VPython | ||
| Line 98: | Line 99: | ||
| ===Handout=== | ===Handout=== | ||
| ==Pre-coding Answers== | ==Pre-coding Answers== | ||
| - | - INSERT PICTURE | + | - {{:repository:terminal_velocity_velocity.png?nolink&600|}} |
| - | - INSERT PICTURE | + | - {{:repository:terminal_velocity_forces.png?nolink&600|}} |
| - | - The equation for terminal velocity is $V=\sqrt{\dfrac{2W}{C\rho A}}$, where | + | - The equation for terminal velocity is $v=\sqrt{\dfrac{2W}{C\rho A}}$, where |
| - | - $W$ is the weight of the coin (N) | + | * $W$ is the weight of the coin (N) |
| - | - this is calculated by multiplying the mass of the coin by the acceleration of gravity: $W= 0.01135 \text{kg} * 9.81 \text{m/s/s} = 0.111 \text{N}$ | + | * this is calculated by multiplying the mass of the coin by the acceleration of gravity: $W= 0.01135 \text{kg} * 9.81 \text{m/s/s} = 0.111 \text{N}$ |
| - | - $C$ is the drag coefficient (1.15, no units) | + | * $C$ is the drag coefficient (1.15, no units) |
| - | - $\rho$ is the density of air (1.2754 kg/m³) | + | * $\rho$ is the density of air (1.2754 kg/m³) |
| - | - $A$ is the area of the coin | + | * $A$ is the area of the coin |
| - | - this is calculated by squaring the radius of the coin and multiplying it by pi: $A= (0.015305 \text{m})^2 * \pi = 0.000736 \text{m²}$ | + | * this is calculated by squaring the radius of the coin and multiplying it by pi: $A= (0.015305 \text{m})^2 * \pi = 0.000736 \text{m²}$ |
| - | - $v=\sqrt{\dfrac{2*0.111}{1.15*1.275*0.000736}}=14.3 \text{m/s}$ | + | * $v=\sqrt{\dfrac{2*0.111}{1.15*1.275*0.000736}}=14.3 \text{m/s}$ |
| ==Post-coding Answers== | ==Post-coding Answers== | ||
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| ---- | ---- | ||
| ====See Also==== | ====See Also==== | ||
| - | * | + | *[[beating_the_train | Beating the Train]] |
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