183_notes:examples:walking_in_a_boat

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183_notes:examples:walking_in_a_boat [2014/10/01 05:50] – pwirving183_notes:examples:walking_in_a_boat [2014/10/01 05:51] (current) – pwirving
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 $x = (\dfrac{m}{M+m})L  \equiv \dfrac{m}{M}L \equiv 0$ when $M>>m$ $x = (\dfrac{m}{M+m})L  \equiv \dfrac{m}{M}L \equiv 0$ when $M>>m$
  
-Another check would be to check what happens when M = 0 then x $\equiv L$, no boat limit+Another check would be to check what happens when M = 0 then x $\equiv L$, i.e. if there was no boat.
  
 $x = (\dfrac{m}{M+m})L  \equiv \dfrac{m}{M}L \equiv L$ when $m>>M$ $x = (\dfrac{m}{M+m})L  \equiv \dfrac{m}{M}L \equiv L$ when $m>>M$
  
 So the motion of the center of mass of a system is dictated by the net external force. So the motion of the center of mass of a system is dictated by the net external force.
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  • Last modified: 2014/10/01 05:50
  • by pwirving