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--- 184_notes:examples:week2_moleoelectrons [2017/08/24 17:24] – [Solution] tallpaul
+++ 184_notes:examples:week2_moleoelectrons [2018/05/17 15:16] (current) – curdemma
@@ Line 1: / Line 1: @@
+[[184_notes:charge|Return to Electric Charge Page]]
-===== Example: How much total charge is in one mole of electrons? =====
+===== Example: Find the total charge for a mole of electrons =====
 How much total charge (in coulombs) is in one mole of electrons?
 ===Facts===
-  * The Avogadro constant is $N_A = 6.022 \cdot 10^{23} \text{ mol}^{-1}$
+  * The Avogadro constant is $N_A = 6.022 \cdot 10^{23} \text{ mol}^{-1}$. This is easy to look up, which is what we did.
-    * Note: When we write the unit as $\text{ mol}^{-1}$, we mean particles per mole.
+    * Note: When we write the unit as $\text{ mol}^{-1}$, we mean particles per mole. We could also write this unit as $mol^{-1}=\frac{1}{mol}$.
-  * All electrons have the same charge, which is $e$ = $-1.602\cdot10^{-19} \text{ C}$.
+  * All electrons have the same charge, which is $e = -1.602\cdot10^{-19} \text{ C}$.
-===Lacking===
+===Goal===
-  * Total Charge
+  * Find the amount of charge in 1 mole of electrons.
-===Approximations & Assumptions===
-  * None here, we have all the information we need.
-===Representations===
-  * The total number of particles $N$ can be found from the number of moles $m$ using the Avogadro constant: $N = m \cdot N_A$.
-  * The total charge $Q$ can be written as the number of particles $N$ times the charge of each particle ($e$, for electrons): $Q=N\cdot e$.
 ====Solution====
-The total number of electrons $N$ is given by
+The total charge $Q$ can be written as the number of particles $N$ times the charge of each particle ($e$, for electrons): $Q=N\cdot e$. We know $e$, and since we know we are interested in exactly 1 mole, we can find $N$:
 \begin{align*}
 N &= 1 \text{ mol} \cdot 6.022 \cdot 10^{23} \text{ mol}^{-1} \\