Both sides previous revision Previous revision | |
184_notes:examples:week5_gauss_ball [2021/06/07 14:00] – [Solution (Part A)] schram45 | 184_notes:examples:week5_gauss_ball [2021/06/07 14:02] (current) – schram45 |
---|
\end{cases} | \end{cases} |
\] | \] |
Outside the ball, the electric field exists as if the ball were a point charge! | Outside the ball, the electric field exists as if the ball were a point charge! It is also important to note that the relationships seen in our above equations also agree with what we already know about insulating spheres of charge. |
====Solution (Part B)==== | ====Solution (Part B)==== |
We repeat the process above for the case that the ball is a conductor. Notice that much of the reasoning is the exact same. We still have spherical symmetry, and we choose the same Gaussian surface. It is pictured below for both r<R and r>R. | We repeat the process above for the case that the ball is a conductor. Notice that much of the reasoning is the exact same. We still have spherical symmetry, and we choose the same Gaussian surface. It is pictured below for both r<R and r>R. |