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--- 183_notes:examples:calcgravforce [2016/09/21 15:23] – [Solution] caballero
+++ 183_notes:examples:calcgravforce [2018/02/09 18:33] (current) – [Solution] hallstein
@@ Line 57: / Line 57: @@
 Results in the magnitude of the force by unit vector (direction).
- $$                = 1.0 \times 10^{29}N \langle -0.7,0,+0.7 \rangle$$
+ $$                = 4.0 \times 10^{20}N \langle -0.7,0,+0.7 \rangle$$
 Results in the vector force, with the x,y,z components interpretable.
- $$                = \langle -7.0 \times 10^{28}, 0, 7.0 \times 10^{28} \rangle N $$
+ $$                = \langle -2.8 \times 10^{20}, 0, 2.8 \times 10^{20} \rangle N $$