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| 183_notes:l_principle [2021/05/11 19:07] – [The Angular Momentum Principle] stumptyl | 183_notes:l_principle [2021/06/03 15:49] (current) – [Systems That Experience No Net Torque] stumptyl | ||
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| ==== Systems That Experience No Net Torque ==== | ==== Systems That Experience No Net Torque ==== | ||
| - | {{ 183_notes:mi3e_11-033.png?300}} | + | [{{ 183_notes:week12_cometearthsun.png?300| Comet orbiting two locations. Location A being a star, and Location B being Earth. Identifying areas of interest in relation to net torque.}}] |
| For some systems, you might be able to choose a location from which to measure the angular momentum where the system experiences no net torque. For example, in the figure to the right a comet orbits a star. The gravitational force vector points from the comet to the star (red arrow). | For some systems, you might be able to choose a location from which to measure the angular momentum where the system experiences no net torque. For example, in the figure to the right a comet orbits a star. The gravitational force vector points from the comet to the star (red arrow). | ||
| - | If you choose the location about which to determine the angular momentum to be the star itself (i.e., location A), then the comet experiences no net torque. Why? Because the position vector that locates the comet points from the star to the comet and is thus along the same line as the gravitational force. The cross product of two parallel or anti-parallel vectors is zero. Hence, the angular momentum of the comet around the star is constant. That constant is not zero; the torque is zero. | + | If you choose the location about which to determine the angular momentum to be the star itself (i.e., location A), then the comet experiences no net torque. Why? Because the position vector that locates the comet points from the star to the comet and is thus along the same line as the gravitational force. The cross product of two parallel or anti-parallel vectors is zero. __//Hence, the angular momentum of the comet around the star is constant. That constant is not zero; the torque is zero.//__ |
| $$\Delta \vec{L}_{sys} = 0 \longrightarrow \vec{L}_{sys, | $$\Delta \vec{L}_{sys} = 0 \longrightarrow \vec{L}_{sys, | ||