Artemis 13 is still not home and beset by troubles. After finding that the circuit (as is) draws too much current from the battery to get the Artemis 13 home, you hit the drawing board to see if there is a way to rearrange the circuit or a proper order or something that will get these brave astronauts on their secret mission home. After several hours of brainstorming, one of your interns has come up with a risky but possibly brilliant solution. They want to take two batteries from the mostly dead Command Ship and use them to help power the Artemis. They propose the following circuit and say they need 140 V ($V_{bat1}$) from the Command Ship battery and only 5 V ($V_{bat2}$) from the backup battery to get them home - one to connect the parachute primers to the environmental control systems and one to help power the guidance computer system. (Remember you found previously that: $R_{FL}=100\Omega$, $R_{PP}=700\Omega$, $R_{CR}=950\Omega$, $R_{GCS}=500\Omega$, $R_{ECS}=300\Omega$, and $R_{CCM}=425\Omega$)

This is the crew of the Artemis 13's last chance. Will this circuit work without drawing any more than the 0.35 A from the main battery?