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| 183_notes:newton_grav_pe [2014/10/17 15:06] – [Newtonian Gravitational Potential Energy] caballero | 183_notes:newton_grav_pe [2021/04/01 12:54] (current) – [Newtonian Gravitational Potential Energy] stumptyl | ||
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| + | Section 6.8 in Matter and Interactions (4th edition) | ||
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| ===== Gravitational Potential Energy ===== | ===== Gravitational Potential Energy ===== | ||
| - | You have read about the [[183_notes: | + | You have read about the [[183_notes: |
| + | |||
| + | ==== Lecture Video ==== | ||
| + | |||
| + | {{youtube> | ||
| ==== (Near Earth) Gravitational Potential Energy ==== | ==== (Near Earth) Gravitational Potential Energy ==== | ||
| - | Earlier, you read how the gravitational potential energy for a system consisting of two objects (The Earth and something on the surface of the Earth) is given by, | + | Earlier, you read how the gravitational potential energy |
| $$\Delta U_{grav} = +mg\Delta y$$ | $$\Delta U_{grav} = +mg\Delta y$$ | ||
| - | where the separation distance is measured from the surface of the Earth. | + | where the separation distance |
| - | However, | + | However, |
| - | ==== Newtonian Gravitational Potential Energy ==== | + | ===== Newtonian Gravitational Potential Energy |
| In general, the gravitational force exerted on a object of mass $m_1$ due to an object of mass $m_2$ is non-constant, | In general, the gravitational force exerted on a object of mass $m_1$ due to an object of mass $m_2$ is non-constant, | ||
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| So for this force, what is the gravitational potential energy? | So for this force, what is the gravitational potential energy? | ||
| - | === Solve the 1-dimensional problem first === | + | ==== Solve the One-Dimensional Problem First ==== |
| Remember that the potential energy change is the negative change in the internal work ($\Delta U = -W_{int}$). So, you can calculate what the work done by the gravitational force would be and use that to determine that change in potential energy in going from location 1 to location 2, | Remember that the potential energy change is the negative change in the internal work ($\Delta U = -W_{int}$). So, you can calculate what the work done by the gravitational force would be and use that to determine that change in potential energy in going from location 1 to location 2, | ||
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| You can compute the work done by the gravitational force as the mass moves from $x=x_1$ to $x=\infty$. | You can compute the work done by the gravitational force as the mass moves from $x=x_1$ to $x=\infty$. | ||
| - | The force on the little mass is given by | + | The force on the little mass at any location $x$ is given by |
| $$F_{grav}(x) = -G\dfrac{Mm}{x^2}$$ | $$F_{grav}(x) = -G\dfrac{Mm}{x^2}$$ | ||
| - | where the minus indicates the force points to the left. Because the displacement ($dx$) is to the right the work done by the gravitational force in this case is negative ($W_{grav} < 0$). This serves as a check for you as you do the calculation; | + | where the minus indicates the force points to the left. Because the displacement ($dx$) is to the right, the work done by the gravitational force in this case is negative ($W_{grav} < 0$). This serves as a check for you as you do the calculation; |
| - | $$W_{grav} = \int_{x_1}^{\infty} F(x)\:dx = -\int_{x_1}^{\infty}G\dfrac{Mm}{x^2}\: | + | $$W_{grav} = \int_{x_1}^{\infty} F(x)\:dx = -\int_{x_1}^{\infty}G\dfrac{Mm}{x^2}\: |
| This potential energy is definitely negative because $x_1$ is a positive value. You can now determine the potential energy change, | This potential energy is definitely negative because $x_1$ is a positive value. You can now determine the potential energy change, | ||
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| $$U(x_1) = -G\dfrac{Mm}{x_1}$$ | $$U(x_1) = -G\dfrac{Mm}{x_1}$$ | ||
| - | === General form of the gravitational potential energy === | + | ==== General form of the gravitational potential energy |
| Thus, in general, if we measure the radial distance from an object the gravitational potential energy varies inversely with the distance, | Thus, in general, if we measure the radial distance from an object the gravitational potential energy varies inversely with the distance, | ||